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• 00:10

DR HERSCHEL KNAPP: Hi, I'm Dr. Herschel Knapp.This video provides an overview of the ANOVAtest, analysis of variance.ANOVA is a lot like the t-test, except insteadof comparing just two groups, the ANOVA testcompares three or more continuous variablesto detect statistically significant differencesbetween the groups.

• 00:32

DR HERSCHEL KNAPP [continued]: [Which group significantly outperforms which?]We could ask which group significantlyoutperformed which?So for our example, we're going to ask the question, what'sthe best way to teach the multiplicationtable to students?Math, as usual, their regular math method, Z-Math,

• 00:53

DR HERSCHEL KNAPP [continued]: an innovative new method, or flash cards.So we have three groups.[Groups 1, 2, & 3]We would take our students and randomlyassign them to one of each of the three groups.Group 1 would get the math as usual lesson.Group 2 would get Z-Math math.

• 01:13

DR HERSCHEL KNAPP [continued]: And Group 3 would be given flash cards to study.After the lesson, we would administer a math testto each of the groups.Everyone would respond to the same test.And from there, we could get a mean score from each group.Group 1 gets a mean of 75.Group 2 gets a mean of 80.And Group 3 gets a mean of 79.

• 01:36

DR HERSCHEL KNAPP [continued]: Now, it's time to make some comparisons to seewhich group outperformed which.The first comparison we could look at is Group 1 to Group 2.Next we could look at Group 1 to Group 3.And then finally, we could look at Group 2 to Group 3.So the ANOVA will produce p-valuesfor each of the pairs of groups.

• 01:58

DR HERSCHEL KNAPP [continued]: And this is what we're going to look atto determine which group statistically significantlyoutperformed which.We'll start with the first pair, Group 1 to Group 2,which renders a p-value of 0.015.Now since the p-value is less than or equal to 0.05,we conclude Z-Math with a mean of 80 statistically

• 02:21

DR HERSCHEL KNAPP [continued]: significantly outperformed math as usual with a mean of 75.We moved on to the next comparison, Group 1 to Group 3,which renders a p-value of 0.026.And again, since the p-value is less than 0.05,we'd conclude that flash cards with a mean of 79 statistically

• 02:42

DR HERSCHEL KNAPP [continued]: significantly outperformed math as usual with a mean of 75.And our final comparison will be to lookat Group 2 versus Group 3.This produces a p-value of 0.631.Now in this case, since the p-value is greater than 0.05,we would conclude that Z-Math with a mean of 80

• 03:05

DR HERSCHEL KNAPP [continued]: did not statistically significantly outperformflashcards with a mean of 79.It did a little bit better, but not enough betterto be statistically significant.For further details on conducting the ANOVA test,please download the videos at sagepub.com/knapp.

• 03:28

DR HERSCHEL KNAPP [continued]: For further reading, please refer to an IntroductoryStatistic using SPSS or PracticalStatistics for Nursing using SPSS-- both by Herschel Knapp.

Video Info

Publisher: SAGE Publications Ltd

Publication Year: 2017

Video Type:Tutorial

Methods: Analysis of variance

Segment Info

Segment Num.: 1

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Abstract

Dr. Herschel Knapp introduces the ANOVA test and provides an example of how to use it to detect statistical significance.